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	<title>LAMP for WEB &#187; sql</title>
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	<description>Linux Apache Mysql Php - Örnek uygulama, ipuçları, döküman, duyuru v.s</description>
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		<title>Update sorgularında &#8220;join&#8221; ve &#8220;replace&#8221;</title>
		<link>http://www.lampforweb.com/index.php/mysql/update-sorgularinda-join-ve-replace/</link>
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		<pubDate>Wed, 05 Nov 2008 13:12:05 +0000</pubDate>
		<dc:creator>longvehicle</dc:creator>
				<category><![CDATA[mysql]]></category>
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		<description><![CDATA[Birden fazla tablodaki kontrollere göre yapacağınız bir update sorgusunu aşağıdaki gibi oluşturabilirsiniz.

UPDATE 	tablo1
	INNER JOIN tablo2 ON tablo1.id=tablo2.id AND tablo2.sehir_id='34'
	SET tablo1.metin=REPLACE&#40;tablo1.metin,'İst.','İstanbul'&#41;
	WHERE tablo1.metin LIKE &#34;%İst.%&#34;

Bu sorgu ile tablo2 ile joinlenen tablo1&#8242;deki metin alnında replace komutu ile değişiklik yapılıyor.
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